How to connect behind a proxy

[LCozzoli]

Hey,
I'm currently using gorilla and wanted to migrate to this more recent library, unfortunately I can't seems to find any info about a proxy support. Is there a way to connect to a websocket server using an http proxy like gorilla does ?

[nhooyr]

Yup, pass in an http.Client configured for your proxy. See DialOptions and net/http docs on proxy configuration for http.Client.

[LCozzoli]

Perfect, thanks!

[LCozzoli]

I'm running into Connection header "keep-alive" does not contain Upgrade issues when connecting

wsURL := "ws://example.com"
proxyURL := "http://proxy_host:proxy_port"
proxyURLParsed, err := url.Parse(proxyURL)
if err != nil {
	log.Fatalf("Failed to parse proxy URL: %v", err)
}
dialer := &websocket.DialOptions{
	HTTPClient: &http.Client{
		Transport: &http.Transport{
			Proxy: http.ProxyURL(proxyURLParsed),
		},
	},
}

conn, _, err := websocket.Dial(context.Background(), wsURL, dialer)
if err != nil {
	log.Fatalf("Failed to connect: %v", err)
}

[nhooyr]

Not sure what you mean by header "keep-alive"? What's the full error message and on what line are you getting it?

[LCozzoli]

Hello,
I think that my request is getting blocked by this line:
https://github.com/nhooyr/websocket/blob/14fb98eba64eeb5e9d06a88b98c47ae924ac82b4/accept.go#LL165C56-L165C56
I get
Failed to connect: WebSocket protocol violation: Connection header "keep-alive" does not contain Upgrade

[nhooyr]

What version of Go are you using?

[LCozzoli]

go version go1.20.2 windows/amd64
The proxy I used to try works with Gorilla, I tried the same code (the closest syntax).
If you have the time and want to reproduce the issue I can give you access to a proxy, add me discord SegFault#0001

[nhooyr]

All good, I'll setup a full go test case as I'll want to ensure this works going forward.

[nhooyr]

Yup, test passes so not sure what you were dealing with. Are you sure your forward proxy is/was working correctly? Was it working with Gorilla?

Closing for now, feel free to comment if you have further information.